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6x^2+24x+18=378
We move all terms to the left:
6x^2+24x+18-(378)=0
We add all the numbers together, and all the variables
6x^2+24x-360=0
a = 6; b = 24; c = -360;
Δ = b2-4ac
Δ = 242-4·6·(-360)
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9216}=96$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-96}{2*6}=\frac{-120}{12} =-10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+96}{2*6}=\frac{72}{12} =6 $
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